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PHP: Arrays and empty()
Topic Started: Mar 25 2005, 03:16 AM (771 Views)
FearKiller Mar 25 2005, 03:16 AM Post #1
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www.drewscripts.com
[ * * * * * ]
 I made a script that posts data from page1 to page2. Page1 has four variables that are set by checkboxes.

Page2 has the following code on it to deal with these four variables in one array
Code:
 
<?php

$array = array("$var1", "$var2", "$var3", "$var4");

if (!empty($array))
{
echo ("The array is not empty");
}
else
{
echo ("The array is empty");
}

?>

Even if the user checks no boxes on page1, the array still shows up as not being empty on page2. If all the variables within the array are empty, then wouldn't the array itself be empty as well? What is in the array that is causing it to not be empty when none of the boxes are checked?
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Stefan Mar 25 2005, 08:08 AM Post #2
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Mew?
[ * * * * * * * ]
 An array is empty when it contains no elements.
If it contains elements, it isn't empty, regardless of those elements being empty or not.
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FearKiller Mar 26 2005, 02:53 AM Post #3
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www.drewscripts.com
[ * * * * * ]
 Oh, I see

Code:
 
<?php

$array = array("$var1", "$var2", "$var3", "$var4");

if (!empty($var1) || !empty($var2) || !empty($var3) || !empty($var4))
{
echo ("The array is not empty");
}
else
{
echo ("The array is empty");
}

?>


That'll work. Thanks for your help.
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Seth Mar 26 2005, 03:39 AM Post #4
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I has a pony
[ * * * * * * * * * ]
FearKiller
March 26, 2005 12:53 AM
Oh, I see

Code:
 
<?php

$array = array("$var1", "$var2", "$var3", "$var4");

if (!empty($var1) || !empty($var2) || !empty($var3) || !empty($var4))
{
echo ("The array is not empty");
}
else
{
echo ("The array is empty");
}

?>


That'll work. Thanks for your help.

Nooooooooooooooooooo!

Code:
 
<?php

$array = array($var1, $var2, $var3, $var4);
$stillEmpty = TRUE;

foreach ($array as $value) {
if (!empty($value)) {
$stillEmpty = FALSE;
break;
}
}

if ($stillEmpty) {
echo("Yarr I'm empty!");
} else {
echo("Yarr I'm full, yum!");
}
?>
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FearKiller Mar 26 2005, 02:10 PM Post #5
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www.drewscripts.com
[ * * * * * ]
Seth
March 26, 2005 02:39 AM
Nooooooooooooooooooo!

Code:
 
<?php

$array = array($var1, $var2, $var3, $var4);
$stillEmpty = TRUE;

foreach ($array as $value) {
if (!empty($value)) {
$stillEmpty = FALSE;
break;
}
}

if ($stillEmpty) {
echo("Yarr I'm empty!");
} else {
echo("Yarr I'm full, yum!");
}
?>

Hmm, that'll work to and looks much better, but shouldn't that last if statement read if($stillEmpty == "TRUE") rather than just if($stillEmpty) :unsure:
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Rory Mar 26 2005, 03:16 PM Post #6
i;m a mess
[ * * * * * * * ]
 nope.

if($stillEmpty) checks whether $stillEmpty is TRUE or FALSE. If you want the condition to do something if false, then just do if(!$stillEmpty)

You could do

if($stillEmpty == TRUE)

but the first method is easier.
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